Question

two dice are thrown simultaneously the probability of getting a sum of 11 ​

Answer 1

Answer:

$\red\bigstar$ Probability of getting a sum of 11 when two dice are thrown simultaneously  = 1/18.

SOLUTION

SAMPLE SPACE WHEN 2 DIE ARE THROWN

(1,1) , (2,1) , (3,1) , (4,1) , (5,1) , (6,1)​

(1,2) , (2,2) , (3,2) , (4,2) , (5,2) , (6,2)

​(1,3) , (2,3) , (3,3) , (4,3) , (5,3) , (6,3)

​(1,4) , (2,4) , (3,4) , (4,4) , (5,4) , (6,4)​

(1,5) , (2,5) ,(3,5) , (4,5) , (5,5) , (6,5)

​(1,6) , (2,6) , (3,6) , (4,6) , (5,6) , (6,6)​

$\boxed{\sf Probability \:of \:an \:event = \dfrac{Number \:of \:Favorable \:outcomes}{Total \:number \:of \:Outcomes} }$

We are asked to find  the probability of getting a sum of 11 ​.

✳ Favorable Events of getting a sum of 11 = (6,5) and (5,6)

✳ Number of Favorable Events = 2

✳ Total Number of events = 6² = 36 Events.

$\sf Probability \: of \: getting\: a \: sum \: of \: 11 = \dfrac{2}{36}$

$\implies$

$\sf Probability \: of \: getting\: a \: sum \: of \: 11 = \dfrac{1}{18}$