Question

Two dice are thrown simultaneously the probability of obtaining total score of 6 is
I

Answer 1

probability=number of favourable out comes/total number of out comes

number of favourable outcomes are 1,5; 2,4; 3,3; 4,2; 5,1

total number of outcomes are 12

probability = 5/12

Answer 2

Two dices are thrown, then the total number of outcomes would be 36 as listed below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (13 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

We have to find the probability of obtaining a total score of 6, i.e., the digits appearing on top of the dices should sum up to 6.

So, Here, the total number of favourable outcomes is... 5 as

(1, 5),

(2, 4),

(3, 3),

(4, 2),

(5, 1)

Each of the above outcomes has the sum equal to 6.

These are the favourable outcomes, i.e, the outcomes we want.

So no. of favourable outcomes = 5.

Probability of an event E is given by:

P(E)=No.of favourable outcomes/Totalno.of outcomes

So, here,

P(E)=5/36

Hope this helps :D

Mark as brainliest plzzz...✌️☺️