Two dice are thrown simultaneously .the probability that the product of the numbers appearing on the top faces of the dice is a perfect square
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13
possible outcome of throwing two dice simultaneously= 36
product of 2 outcome having product a perfect square: (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)
favourable outcome = 6
probability= 6/36
= 1/6
product of 2 outcome having product a perfect square: (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)
favourable outcome = 6
probability= 6/36
= 1/6
Answered by
8
The probability of getting a square number as product of number on top faces is 2/9
1) Rolling a dice gives 6 possible outcomes.
2) Rolling 2 dice gives 6*6 = 36 possible outcomes.
3) The favorable outcome is that product of the numbers equal a square number.
4) Possible square numbers are : 1,4,9,16,25,36
5) Total Ways to form 1 is 1 = 1,1
Total Ways to form 4 is 3 = 1,4 2,2 4,1
Total Ways to form 9 is 1 = 3,3
Total Ways to form 16 is 1 = 4,4
Total Ways to form 25 is 1 = 5,5
Total Ways to form 36 is 1 = 6,6
6) Hence the total favorable outcomes are :-8
7) The probability would be = 8/36 = 2/9
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