two dice are thrown simultaneously then the probability of geeting sum 9 is
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Step-by-step explanation:
In two throws of a die, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) =n(E)/n(S)=4/36=1/9.
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Answer:
two dice are thrown simultaneously then the probability of geeting sum 9 is 4
Step-by-step explanation:
(3,6),(4,5),(5,4),(6,3)
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