Math, asked by milivansh7392, 1 year ago

Two dice are thrown simultaneously. What is teh probability that (i) 5 will not come up on either of them? (ii) 5 will come up on at least one? (iii) 5 will come up at both dice?

Answers

Answered by Anonymous
6
p (5 will not come up on either of them ) = 26/36

p (5 will come up at least one ) = 11/36

p (5 will come up at both side) = 1/36


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Answered by brainlllllllllly
0

Two dice thrown,

So, the total outcomes = 6² = 36

1. 5 will not come either of them

Favourable Outcomes = 36-12 = 24

P( not e) = Favorable outcomes/total Outcomes

= 24/36 = 2/3

2. 5 will come at least once

Favorable outcomes = 12

P(e) = Favorable outcomes/total Outcomes

=12/36 = 1/3

3. 5 will come both twice

Favourable Outcomes =2

P(e) = Favorable outcomes/total Outcomes

= 2/36

= 1/18

Hopefully it helps you...

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