Question

Two dice are thrown simultaneously.What is the ly find the probability of getting a doublet

Answer 1

Answer:

1/6

Step-by-step explanation:

doublet pairs: {1,1},{2,2}.....six pairs are possible

total outcomes possible:

dice 1        dice 2

1                   1

1                   2

1                   3

1                   4

1                   5

1                   6

2                   1

2                   2

2                  3

2                  4

2                  5

2                   6

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...

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i.e 6*6...36 such pairs are possible

therefore Probability=favourable/total=6/36=1/6

Answer 2

Question  -

Two dice are thrown simultaneously.What is the ly find the probability of getting a doublet.

Solution -

In the above question , two die are thrown simultaneously .

We have to calculate the probability of getting a doublet .

First let us find the required sample space .

$\left[\begin{array}{ccc}(1, 1 ) &(1, 2 ) &( 1, 3 ) & ( 1, 4 ) & ( 1, 5 ) & ( 1, 6 ) \\ \\(2, 1 ) &(2, 2 ) &( 2, 3 ) & ( 2, 4 ) & ( 2, 5 ) & ( 2, 6 ) \\\\(3, 1 ) &(3, 2 ) &(3, 3 ) & ( 3, 4 )&(3, 5 )&(3, 6 )\\ \\ (4, 1 )&(4, 2 )&(4, 3 )&(4, 4 )&(4, 5 )&(4, 6 ) \\ \\ (5, 1 )&(5, 2 )&(5, 3)&(5, 4 )&(5, 5 )&(5, 6 ) \\ \\ (6, 1 )&(6, 2 )&(6, 3 )&( 6, 4 )&( 6, 5 )&(6, 6 ) \end{array}\right]$

The number Of chances to get a doublet = 6

Sample Space = 36

Hence, required probability is [ 6 ] / [ 36 ] or [ 1 ] / [ 6 ] .