Question

Two dice are thrown simultaneously. What is the probability that the sum of the two numbers appearing on the top is 13.

Answer 1

Answer:

P(A) = 0/36

Step-by-step explanation:

Let sample space by S :

S = { (1,1);(1,2);(1,3);(1,4);(1,5);(1,6)

(2,1);(2,2);(2,3);(2,4);(2,5);(2,6)

(3,1);(3,2);(3,3);(3,4);(3,5);(3,6)

(4,1);(4,2);(4,3);(4,4);(4,5);(4,6)

(5,1);(5,2);(5,3);(5,4);(5,5);(5,6)

(6,1);(6,2);(6,3);(6,4);(6,5);(6,6) }

Therefore, n(S) = 36

Event A : The sum of two numbers appearing on the top is 13

A = { }

Therefore n(A) = 0

p(A) = n(A) / n(s)

p(A) = 0 /36