Question

two dice are thrown simultaneously what is the probability of getting a doublet or total of 4​

Answer 1

Answer:

P(getting a doublet or total of 4)= 4/36=1/9

Step-by-step explanation:

Total outcomes when 2 dices are thrown-

(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Favourable outcomes-

Doublet of 4= (4,4)

Total of 4= (1,3) (3,1) (2,2)

Hence total outcomes=36

Total favourable outcomes= 4

Therefore, Probability= 4/36=1/9

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