Question

Two dice are thrown simultaneously what is the probability of sum of numbers appearing non-prime numbers.
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Wrong answer is not expectable.
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Spam is not expectable.
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Give right answer.
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Good answer will be brainlist.​

Answer 1

Answer:

Step-by-step explanation:

The total number of possible outcomes in this case is 36—

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Out of the listed possibilities, the favorable outcomes for Prime number are —  (1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5)  =15

Hence, the number of favorable outcomes for non prime is 36-15= 21.

Therefore, the required probability is   36/21 = 12/7  

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Answer 2

It is not possible, so its probability is zero.

HOPE IT HELPS YOU CARRY ON LEARNING