two dice are thrown simultaneously what is the probability of getting two numbers whose product is even
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ok answer is 3/4 hope you got it
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Answer:
3/4
Step-by-step explanation:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2),
(3, 4),(3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4),
(5, 6), (6, 1),(6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
Therefore, n(E) = 27.
Therefore, P(E) = n(E)/n(S) = 27/36 = 3/4
Hope it is helpful...
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