Two dice are thrown simultaneously. what is the probability that the sum of the numbers shown on the two dices will be a prime number?
Answers
Answered by
23
total events=6×6=36
sum is a prime number=(1,1),(1,2),(1,4),(1,6),(2,1,(2,3),(2,5),(3,2),(3,4),(,4,1),(4,3),(5,2),(5,6),(6,1),(6,5)
total=14
P=14/36=7/18
sum is a prime number=(1,1),(1,2),(1,4),(1,6),(2,1,(2,3),(2,5),(3,2),(3,4),(,4,1),(4,3),(5,2),(5,6),(6,1),(6,5)
total=14
P=14/36=7/18
Answered by
13
Answer:
total events=6×6=36
sum is a prime number=(1,1),(1,2),(1,4),(1,6),(2,1,(2,3),(2,5),(3,2),(3,4),(,4,1),(4,3),(5,2),(5,6),(6,1),(6,5)
total=14
P=14/36=7/18
Step-by-step explanation:
Similar questions
Computer Science,
8 months ago
Math,
8 months ago
Geography,
8 months ago
Math,
1 year ago
Physics,
1 year ago