Question

Two dice are thrown simultaneously what is the probability of

1.. getting a doublet
2..getting sum of 10

Answer 1

n(s)= 36

n(getting a doublet) =n(E)=(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)=6

p(E)=?

p(E)=n(E)/n(s)

p(E)=6/36=1/6

n(s)=36

n(A)=(5,5),(6,4),(4,6)=3

p(A)=?

p(A)=n(A)/n(s)

p(A)=3/36

p(getting sum) =1/12

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Answer 2

I hope u will understand