Two dice are thrown simultaneously. What is the probanlity that the sum of the numbers appearing on the dice is (1)7 (2)1 (3)a prime number
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total outcome=36
i) sum 7 number=6
p=6/36=1/6
ii) sum 1 number =0
p=0
iii) sum prime number=15
p=15/36=5/12
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i) sum 7 number=6
p=6/36=1/6
ii) sum 1 number =0
p=0
iii) sum prime number=15
p=15/36=5/12
___i_hope_it_help___
__thank_you__
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