Two dice are thrown the probability of getting an odd number on the first die and multiple of 3 on the other is
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10
Answer:
Step-by-step explanation:
odd no. on the first die
1 , 3 , 5
multiple of 3 on the other die
3 , 6
now lets see the combination of these two events happening simultaneously
as the question says
(1,3) , (1,6) , (3,3) , (3,6) , (5,6) , (5,3)
total no of favorable events = 6
total no of events throwing two dice simultaneously = 6² = 36
so probability = 6/36 = 1/6
Answered by
0
Answer:
Number of favorable outcomes = 6
Total number of outcomes = 36
So, Probability = 6/36
= 1/6
Therefore Probability is 1/6
Hope This Is Helpful .
Step-by-step explanation:
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