Question

Two dice are thrown.The probability that the number appered have a sum of 8,if it is known that the second dice always exhibits 4,is

Answer 1

Answer:

1/6

Step-by-step explanation:

Event A :-Numbers appeared have a sum 8

             {(2,6),(6,2),(3,5),(5,3),(4,4)}

Event B:-second die always exhibit 4

             {(1,4),(2,4),(3,4),(4,4),(5,4),(6,4)}

A n B ={(4,4)}   (

P(B/A)= [P(BnA)]/P(B)

            =[1/36 ]  / [6/36]  

              =1/6.

Note: n is intersection symbol.