two dice are thrown together. determine the probability of two coming on the first die and multiple of three on their die
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Answered by
10
Answer:
When two dice are thrown , there are 6×6, or a total of 36 possibilities.
There are two multiples of three in a dice : 3, 6
So, favorable events would be
(2,3) & (2,6)
Thus , out of 36 there are two favorable events.
Thus , required probability
=2/36
Or 1/18.
Answered by
2
Answer:
probability = ¼
Step-by-step explanation:
probability of 2 = 1/12
because there are two dice
Probability of multiple of 3 is 2/12
add them
= 2/12 + 1/12
= 3/12
= 1/4
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