two dice are thrown together .find probability of getting doublet of prime numbers
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Answered by
26
Given that Two dice are thrown.
So, possible outcomes are n(S) = 6^2
= 36.
Let A be the event of getting doublet of prime numbers.
n(A) = {2,2},{3,3},{5,5}
= 3.
Required probability P(A) = n(A)/n(S)
= 3/36
= 1/12.
Hope this helps!
So, possible outcomes are n(S) = 6^2
= 36.
Let A be the event of getting doublet of prime numbers.
n(A) = {2,2},{3,3},{5,5}
= 3.
Required probability P(A) = n(A)/n(S)
= 3/36
= 1/12.
Hope this helps!
sanya55:
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