Question

two dice are thrown together .find probability of getting doublet of prime numbers
please answer fast

Answer 1

Given that Two dice are thrown.

So, possible outcomes are n(S) = 6^2

                                                     = 36.


Let A be the event of getting doublet of prime numbers.

n(A) = {2,2},{3,3},{5,5}

       = 3.


Required probability P(A) = n(A)/n(S)

                                           = 3/36

                                           = 1/12.


Hope this helps!

Answer 2

Hi,

Please see the attached file !


Thanks