two dice are thrown together find the probability of an event of getting numbers whose sum is divisible by 4
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Two dice are thrown simultaneously.
∴ Total no. of outcomes = 6² = 36.
If the sum is divisible by 4, then the possible sums are 4, 8 and 12.
3 outcomes in which the sum is 4:
(1, 3), (2, 2) (3, 1)
5 outcomes in which the sum is 8:
(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)
1 outcome in which the sum is 12:
(6, 6)
∴ No. of favourable outcomes = 3 + 5 + 1 = 9.
Probability = 9/36 = 1/4.
Hope this helps.
Plz ask me if you've any doubts.
Thank you. :-))
kalpithakngowda:
karnataka
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