Math, asked by nareshjha224, 11 months ago

two dice are thrown together find the probability of getting different number on both dice

Answers

Answered by saulat724

Answer:

2/36 because 36 is the favourable outcome

Answered by Mihir1001

$\bold{Answer:}$

$\huge\boxed{\fcolorbox{red}{white}{5/6}}$

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$\bold{Step-by-step-explaination:}$

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On throwing two dice together, following outcomes can be obtained :

$S = [(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),$

$\: \: \: \: \: \: \: \: \: \: (2,1),(2,2),(2,3),(2,4),(2,5),(2,6),$

$\: \: \: \: \: \: \: \: \: \: (3,1),(3,2),(3,3),(3,4),(3,5),(3,6),$

$\: \: \: \: \: \: \: \: \: \: (4,1),(4,2),(4,3),(4,4),(4,5),(4,6),$

$\: \: \: \: \: \: \: \: \: \: (5,1),(5,2),(5,3),(5,4),(5,5),(5,6),$

$\: \: \: \: \: \: \: \: \: \: (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)]$

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therefore, n(S) = 36

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let $E_1 = event \: of \: getting \: different \: numbers \: on \: both \: the \: die.$

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therefore,

$E_1 = [(1,2),(1,3),(1,4),(1,5),(1,6),$

$\: \: \: \: \: \: \: \: \: \: (2,1),(2,3),(2,4),(2,5),(2,6),$

$\: \: \: \: \: \: \: \: \: \: (3,1),(3,2),(3,4),(3,5),(3,6),$

$\: \: \: \: \: \: \: \: \: \: (4,1),(4,2),(4,3),(4,5),(4,6),$

$\: \: \: \: \: \: \: \: \: \: (5,1),(5,2),(5,3),(5,4),(5,6),$

$\: \: \: \: \: \: \: \: \: \: (6,1),(6,2),(6,3),(6,4),(6,5).]$

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therefore, $n(E_1) = 30$

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hence, $P(E_1) = \frac{n(E_1)}{n(S)} = \frac{30}{36} = \frac{5}{6}$

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two dice are thrown together find the probability of getting different number on both dice