Two dice are thrown together find the probability of getting sum equal 8
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3
It's Probability Is 0. The Sum Is 7.
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8
First die there are 6 possible outcomes for the second
Therefore
Possible outcomes ⇒ 6 × 6 = 36
Sum should p + q = 8 :-
★2+6=8
★3+5=8
★4+4=8
★5+3=8
★6+2=8
536
36
5
{5}{36}}
★ 365
Therefore
Possible outcomes ⇒ 6 × 6 = 36
Sum should p + q = 8 :-
★2+6=8
★3+5=8
★4+4=8
★5+3=8
★6+2=8
536
36
5
{5}{36}}
★ 365
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