Question

two dice are thrown together find the probabilty that the sum of two numbers will be multiple of 4​

Answer 1

Answer:

here n(S)=36

the possibilities are A = {(1,3),(2,2),(3,1),(2,6),(3,5),(4,4),(5,3),(6,2)}

therefore n(A)=8

therefore probability of getting two numbers whose sum will be multiple of 4 is n(A)/n(s)

=8/36

=2/9

Answer 2

Answer:

two dice are thrown together find the probabilty that the sum of two numbers will be multiple of 4