Question

Two dice are thrown together let a be the event of getting six on the first time and be the event of getting 2 on the second die the value of p (a¥b) is

Answer 1

Hey !!

According to question

   A = {(6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6)}

  B = {(1,2) , (2,2) , (3,2) , (4,2) , (5,2) , (6,2)}

        A ∩ B = {(6,2)}

Now, P(A) = $\frac{6}{36} = \frac{1}{6}$

P(B) = $\frac{6}{36} = \frac{1}{6}$

  P (A ∩ B) = $\frac{1}{36}$

Now, we have P(A).P(B) = 1/6 × 1/6 = $\frac{1}{36}$

    = P(A ∩ B)

=> A and B are independent events.

Good luck !!