Question

Two dice are thrown together what is the probability number 1 does not appear on both

Answer 1

SOLUTION

TO DETERMINE

The probability that the number 1 does not appear on both when two dice are thrown together

EVALUATION

Here it is given that two dices are thrown together

Therefore the total number of possible outcomes = 36

Let A be the event that the number 1 does appear on both when two dice are thrown together

Then the event point for the event A is ( 1 , 1)

So the total number of possible outcomes for the event A is 1

So the probability for the event A is

$\displaystyle \sf{ P(A)\: = \frac{1}{36} }$

Hence the probability that the number 1 does not appear on both when two dice are thrown together

= $\displaystyle \sf{ P(\bar{A})\: = 1 - \frac{1}{36} }$

$\displaystyle \sf{ = \frac{36 - 1}{36} }$

$\displaystyle \sf{ = \frac{35}{36} }$

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