Question

Two dice are thrown together what is the probability of getting a total of at least 6

Answer 1

A={(1,1) (1,2)( (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4)
(5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}
P(A)= 5/36 is the ans hope it helps you

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Answer 2

Answer: No.of outcomes whose sum is not 6\total outcomes.

>Total outcomes- 6*6 = 36

>No. Of outcomes whose sum is not 6 = 26

>Now,

26/36 = 13/18.

Answer: 13/18.