two dice are thrown together what is the probability that the sum of the numbers on the two faces is 8??
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Two dice are thrown together .What is the probability that the sum of the number on the two faces is divided by 4 or 6.
A) 7/18
B) 14/35
C) 8/18
D) 7/35
Answer: A) 7/18
Explanation:
Clearly, n(S) = 6 x 6 = 36
Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6.
Then,E = {(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6)}
n(E) = 14.
Hence, P(E) = n(E)/n(S) = 14/36 = 7/18
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