Question

Two dice are thrown. What is probability of getting (i) the sum is 10 (ii) atleast 10

Answer 1

Question no 1
answer is 3/36=1/12. (4,6) ; (5,5) ; (6,4)
Question no 2
answer is 6/36=1/6. (4,6) ; (5,5) ; (5,6) ; (6,4) ; (6,5) ; (6,6)
I hope..... It is helpful

Answer 2

$\underline{ \underline{ \mathfrak{Answer}}} : - \\ \\ n \: (e) = 0.166 \: \\ \\ \underline{ \underline{Step - by \: - step \: \: explanation}} : -$

Given:-

When we throw two dice simultaneously

Then total outcome = 36

The outcomes that have atleast 10 are

(4,6) ,(6,4) ,(5,6) ,(6,5) ,(6,6) ,(5,5)

Favourable outcome = 6

Then ,

$\implies \: n \: (e) = \frac{6}{36} \\ \\ n \: (e) = \frac{1}{6}= 0.166$