Question

Two dice are thrown, what is the probability that both the dices are not having the same number.

Answer 1

Answer:

The dice are not either particular number.

The probability of one dice not being either of two numbers is 4/6, so the probability of both dice fitting this condition is 4/6 x 4/6 = 16/36.

Answer 2

List of all the possibles outcomes :-

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Probability of having same number P(S) = 6 / 36 = 1 / 6

Probability of having different number P(D) = 1 - P(S)

                                                                            = 1 - 1/6 = 5/6