two dice are thrown. what is the probability that the sum of the number on their upper surface is 10
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Answered by
13
Answer:
2/10
Step-by-step explanation:
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Answered by
1
Answer:
1/6
Step-by-step explanation:
Two dice are thrown
∴ Sample space
S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),
(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),
(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
∴n(S)=36
(1) A={(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}
n(A)=6
Probability, P(A) = n(A)/n(S) = 6/36 = 1/6
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