Question

Two dice are tossed the probability that the score is a prime number is

Answer 1

total outcomes =36

no. of die =2

no.of prime no.s in a 2,3 and 6

possible outcomes =15 then

the probability is 15/36

when reduced is 5/12

Answer 2

Total outcomes=36

Let, E-> The score is a prime number.

No. of probable outcomes = 15

Therefore, P(E) =

$\frac{15}{36} \\ = \frac{5}{12}$

(PS- In the above picture, total outcomes are mentioned and the ticked outcomes refer to the ones whose total score is a prime number)