Question

Two dice are tossed together. Find the number of outcomes where the sum is equal to 8​

Answer 1

Answer:

Hence, the probability of getting a sum equal to 8 is 365.

Step-by-step explanation:

hope it helps

Mark as brainleast

Answer 2

$\fbox \red{Required Solution:}$

The possible outcomes when two dice are thrown together are:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6). 

Therefore,

The number of possible outcomes when two dice are thrown is 36.

Now, the possible outcomes of getting a sum equal to 8 is {(2,6),(3,5),(4,4),(5,3),(6,2)}, which means the number of favourable outcome is 5.

$\implies$Therefore, probability P of getting a sum equal to 8 is:

$\sf{P = \frac{5}{36} }$

$\red \bigstar$Hence, the probability of getting a sum equal to 8 is  $\sf{\frac{5}{36} }$.

Thank you!!

@itzshivani