Question

Two dice are tossed together write all possible outcomes of this experiment. Find the probability of getting (i) 7 as the sum (ii) a sum greater than 10. (iii) a sum less than 13.​

Answer 1

Answer:

If Two Dices Are tossed There are 36 possible outcomes are :-

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

(I) there are total 6 favourable outcomes to sum of 7 so possibility is

$\frac{6}{36 }$ = $\frac{1}{6}$

(II) there are total 3 favourable so possibility is :-

$\frac{3}{36} = \frac{1}{12}$

(iii) there are 36 favourable outcomes which favours this so do is :-

$\frac{36}{36} = 1$

Hope this helped you Pls mark my answer as brainliest answer

Answer 2

Answer:

i think no 3 - a sum less than 13

Step-by-step explanation:

if my answers is correct plz mark me as brainlist