Two dice (each bearing number 1 to 6)are rolled together. Find the probability that the sum of the numbers on the upper most faces of two dice is (i) 4 or 5 . (ii) 7 , 8 or 9 . (iii) 6(iv) more than 10. (Class 6 Maths Sample Question Paper in CBSE)
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Total no. of outcomes= 36
(I) Favourable outcomes= 1+3, 1+4, 2+2, 2+3, 3+1, 3+2, 4+1
Total no. of favourable outcomes= 7
Req. probability= 7/36
(ii) Favourable outcomes= 1+6, 2+5, 2+6, 3+4, 3+5, 3+6, 4+3, 4+4, 4+5, 5+2, 5+3, 5+4, 6+1, 6+2, 6+3
Total no. of outcomes= 15/36= 5/12
(iii) Favourable outcomes= 1+5, 2+4, 3+3, 4+2, 5+1
Total no. of favourable outcomes= 5
Req. probability= 5/36
(iv) Favourable outcomes= 5+6, 6+5, 6+6
Total no. of favourable outcomes= 3
Req. probability= 3/36= 1/12
(I) Favourable outcomes= 1+3, 1+4, 2+2, 2+3, 3+1, 3+2, 4+1
Total no. of favourable outcomes= 7
Req. probability= 7/36
(ii) Favourable outcomes= 1+6, 2+5, 2+6, 3+4, 3+5, 3+6, 4+3, 4+4, 4+5, 5+2, 5+3, 5+4, 6+1, 6+2, 6+3
Total no. of outcomes= 15/36= 5/12
(iii) Favourable outcomes= 1+5, 2+4, 3+3, 4+2, 5+1
Total no. of favourable outcomes= 5
Req. probability= 5/36
(iv) Favourable outcomes= 5+6, 6+5, 6+6
Total no. of favourable outcomes= 3
Req. probability= 3/36= 1/12
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this is so hard i can't do
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