Question

Two dice is thrown at random find the probability of getting a sum of 8

Answer 1

Answer:

5/36

Step-by-step explanation:

p(getting the sum is 8) = no. of outcomes/ total no. of outcomes

no. of outcomes = (2,6), (3,5), (4,4), (5,3), (6,2) = 5 outcomes.

total =36

=> 5/36

Answer 2

Answer:

total no of outcome = 36(1,2),(1,3),(1,4),(1,5),(1,6)(1,1)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

favourable outcome =5 (2,6)(4,4)(3,5)(5,3)(6,2)

probability= 5/36

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