Question

Two dice marked 1 to 6 on its faces are thrown simultaneously twice. Find the probability of
the numbers on its faces whose difference is 3.
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Answer 1

Step-by-step explanation:

S = { 1,2,3,4,5,6}

n(S) = 6

event A = the number on its face whose difference is 3

A = { 3,6}

n(A) = 2

p(A) = n(A)/n(S)

=2/6

=1/3