Two dice marked 1 to 6 on its faces are thrown simultaneously twice. Find the probability ofthe numbers on its faces whose difference is 3
Answers
Answered by
6
Answer:
Step-by-step explanation:total not outcomes=36
Favorable outcomes =12
Probability=12/36=1/3
Please mark as brainlist
Answered by
4
The probability that the difference between the number on the faces of the two dice is 3 is equal to 1/6.
Total number of outcomes when two dice are rolled = 36
Total number of favourable outcomes when the difference be the numbers of the faces is 3 = 6
{(6,3),(3,6),(5,2),(2,5),(1,4),(4,1)}
Total probability = total favourable outcomes/ total number of possible outcomes
= 6/36
= 1/6
Similar questions