Question

two dice numbered 1 to 6 are rolled simulataneously. find the probability getting a prime number as the sum

Answer 1

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Hey!!
Here's your answer!!

N(S) = (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
            (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
            (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
            (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
            (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
            (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  = 36

P ( Getting Prime Number as the sum ) =  (1,1) (1.2) (1,4) (1.6) (2,1) (2,3)                                                                         (2,5) (3,2) (3,4) (4,1) (4,3) (5,2)                                                                         (5,6) (6,1) (6,5)  = 15

Probability = 15/36 = 5/12

Therefore Probability of getting sum as prime number is 5/12 .

Hope it helps!!
Cheers!!
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