Two dice,one blue and one grey,are thrown at the same time.What is the probability that the sum of two numbers appearing on the top of the dice is (i) 8? (ii) greater than 8 but less than or equal to 12?
Answers
Answer:
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Step-by-step explanation:
In a throw of pair of dice, blue and grey, total no of possible outcomes=36(6×6) which are
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
E⟶ event of getting sum on 2 dice as 2
No. of favorable outcomes =1 (i.e.,(1,1))
Probability, P(E)=
TotalNo.ofPossibleOutcomes
No.ofFavorableOutcomes
P(E)=
36
1
E⟶ event of getting sum as 3
No. of favorable outcomes =2(i.e.,(1,2)(2,1))
P(E)=
36
2
=
18
1
E⟶ event of getting sum as 4
No. of favorable outcomes =3(i.e.,(3,1)(2,2)(1,3))
P(E)=
36
3
=
12
1
E⟶ event of getting sum as 5
No. of favorable outcomes =4(i.e.,(1,4)(2,3)(3,2)(4,1))
P(E)=
36
4
=
9
1
E⟶ event of getting sum as 6
No. of favorable outcomes =5(i.e.,(1,5)(2,4)(3,3)(4,2)(5,1))
P(E)=
36
5
E⟶ event of getting sum as 7
No. of favorable outcomes =6(i.e.,(1,6)(2,5)(3,4)(4,3)(5,2)(6,1))
P(E)=
36
6
=
6
1
E⟶ event of getting sum as 8
No. of favorable outcomes =5(i.e.,(2,6)(3,5)(4,4)(5,3)(6,2))
P(E)=
36
5
E⟶ event of getting sum as 9
No. of favorable outcomes =4(i.e.,(3,6)(4,5)(5,4)(6,3))
P(E)=
36
4
=
9
1
E⟶ event of getting sum as 10
No. of favorable outcomes =3(i.e.,(4,6)(5,5)(6,4))
P(E)=
36
3
=
12
1
E⟶ event of getting sum as 11
No. of favorable outcomes =2(i.e.,(6,5)(5,6))
P(E)=
36
2
=
18
1
E⟶ event of getting sum as 12
No. of favorable outcomes =1(i.e.,(6,6))
P(E)=
36
1
Step-by-step explanation:
your answer is in the picture
hope it helps you
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