Question

two dice , one blue and one red are thrown simultaneously.What is the probability of getting a total of less than 12?​

Answer 1

2 die are thrown..

So the total outcomes will be 36

And the probability of getting a total of less than 12 are (1,1)(1,2)(1,3),(1,4),(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

So probability is 35/36

Answer 2

Answer:

if two dices are thrown, the total possible outcomes will be: <br> (1,1) , (2,1) , (3,1) , (4,1) , (5,1) , (6,1) <br> (1,2) , (2,2) , (3,2) , (4,2) , (5,2) , (6,2) <br> (1,3) , (2,3) , (3,3) , (4,3) , (5,3) , (6,3) <br> (1,4) , (2,4) , (3,4) , (4,4) , (5,4) , (6,4) <br> (1,5) , (2,5) , (3, 5) , (4,5) , (5,5) , (6,5) <br> (1,6) , (2,6) , (3,6) , (4,6) , (5,6) , (6,6) <br> now, total possible outcomes are 36 <br> (i) outcomes = (2+6) , (3+5), (4+4) , (5+3), (6+2) <br> P(SUM=8) =

<br> (ii) outcomes= 0 <br> P(SUM=13) =

<br> (iii) outcomes= (1+1) , (1+2), (1+3), (1+4), (1+5), (1+6), (2+1), (2+2), (2+3), (2+4), (2+5), (2+6), (3+1), (3+2), (3+3), (3+4), (3+5), (3+6), (4+1),(4+2),(4+3),(4+4) , (4+5), (4+6), (5+1) , (5+2), (5+3), (5+4), (5+5), (5+6), (6+1), (6+2),(6+3),(6+4),(6+5),(6+6) <br> P(SUM<=12) =