Two dice thrown at the same time and the product of number appearing on them is noted. Find the probability that the product is a prime number
Answers
Answered by
65
When two dice are thrown together, total outcomes = 6^2 = 36
Event: the product of number appearing on them is a prime.
E = {(1,2), (1,3), (1,5), (2,1), (3,1), (5,1)}
number of favourable outcomes = 6
Probability = 6/36 = 1/6
Event: the product of number appearing on them is a prime.
E = {(1,2), (1,3), (1,5), (2,1), (3,1), (5,1)}
number of favourable outcomes = 6
Probability = 6/36 = 1/6
sufiyan767832:
your answer is wrong
Why do you think it's wrong?
Understand the question properly once. It's not like the ones normally given in textbooks
prime number has one and itself as factors.
Question: Find the probability that the PRODUCT is a prime number
(1,2),(1,3),(1,5),(2,1),(3,1),(5,1) all these products are prime numbers
Oh yeah... Sorry!!!
Thanks
Answered by
31
When two dice are thrown, the possible products on the outcomes =[1, 2,3,4,5,6,8,9,10,12,15, 16,18,20,24,25,30,36] there fore n=18
Let E be the event of getting the product on upper faces of the dice is a prime number. E=[2, 3,5]
n(E)=3
P(E)=3/18=1/6
Let E be the event of getting the product on upper faces of the dice is a prime number. E=[2, 3,5]
n(E)=3
P(E)=3/18=1/6
Please check your answer. Answer is not 1/6
Thank you!:))
Similar questions