Question

two dice thrown find probability

(a)the number on upper face of the first die is less than the number on the upper face of second

Answer 1

Answer:

Step-by-step explanation:two documents are thrown

No. Of outcome/No of possible outcome- 2/6

1/3(ans)

Answer 2

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
n(S)=36
let A be the event of getting the number on upper face of the first die is less than the number of the upper face of second die2
A={(1,2),(1,3),(1,4),(1,5),(1,6),
(2,3),(2,4),(2,5),(2,6),
(3,4),(3,5),(3,6),
(4,5),(4,6),
(5,6)}
n(A)=15
p(A)=n(A)/n(S)
p(A)=15/36
p(A)=5/12
hope this is helpful