Question

two dice thrown what is the probability of getting the multiple of 3 on the first dice​

Answer 1

Answer:

Step-by-step explanation:

Sample space =(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4), (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

n(S)=36

A=(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

n(A)=12

P(A)=n(A)/n(S)

=12/36

=1/3