Question

Two dices are rolled once find the probability of getting such numbers on the two dice whose product is 12

Answer 1

2×6=12
3×4=12
4×3=12
6×2=12
so the possible outcomes are 4and the total outcomes are 36.so
P (getting such no.s whose product is 12)=4/36
so the answer is 1/9.

HOPE IT HELPS YOU!!!!!!!!........

Answer 2

Answer:

$\text{Probability}=\frac{1}{9}$

Step-by-step explanation:

Given : Two dices are rolled once.

To find : The probability of getting such numbers on the two dice whose product is 12.

Solution :

When two dice rolled once the outcome will be,

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Favorable outcome are :

2×6=12

3×4=12

4×3=12

6×2=12

So, Favorable outcome = 4

Total number of outcome = 36

$\text{Probability}=\frac{4}{36}$

$\text{Probability}=\frac{1}{9}$