two dices are rolled simultaneously find the probability of getting sum of numbers as at least 10
Answers
your answer is in my given pics open it and and if you any problem then ask me by the help of comments
Answer:
A) \text{Probability}=\frac{1}{6}Probability=
6
1
B) \text{Probability}=\frac{5}{12}Probability=
12
5
Step-by-step explanation:
Given : Two dices are thrown simultaneously.
To find : The probability of getting
(A) A total of at least 10
(B) The sum as a prime number
Solution :
When two dice rolled once the outcome will be,
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Now,
\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}Probability=
Total number of outcome
Favorable outcome
(A) A total of at least 10
Favorable outcome are : (4,6), (5,5), (5,6), (6,4), (6,5), (6,6)
So, Number of favorable outcome = 6
Total number of outcome = 36
\text{Probability}=\frac{6}{36}Probability=
36
6
\text{Probability}=\frac{1}{6}Probability=
6
1
(B) The sum as a prime number
Favorable outcome are : (1,1) (1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (4,1) (4,3) (5,2) (5,6) (6,1) (6,5)
So, Number of favorable outcome = 15
Total number of outcome = 36
\text{Probability}=\frac{15}{36}Probability=
36
15
\text{Probability}=\frac{5}{12}Probability=
12
5
