Question

two dices are rolled simultaneously. write the possible outcomes. If the counts ate added then find the probability of getting Sum 4 and 12​

Answer 1

Answer:

P(sum is 4)= 1/12

P(sum is 12)= 1/36

Step-by-step explanation:

Possible Outcomes are:-

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

Total Outcomes=36

If the sum is 4...

P(sum is 4)= 3/36= 1/12 {(1,3),(2,2),(3,1)}

If the sum is 12...

P(sum is 12)= 1/36 {(6,6)}