Question

Two dices are thrown at the same time. What is probabitlity of getting odd or prime number

Answer 1

S = { (1,1)....... }

n(S) = { 36 }

Let A be the event if Getting odd

A = { (1,2),(1,4),(1,6),(2,1), (2,3),(2,5),(3,2),(3,4),(3,6),(4,1),(4,3),(4,5),(5,2),(5,4)(5,6),(6,1),(6,3),(6,5) }

n(A) = { 18 }

P(A) = n(A)÷n(S)

P(A) = 18÷36

P(A) = 1÷2 or 1 upon 2

Let the event of Prime number be B

B = { (1,1),(1,2),(1,4),(1,6)

(2,1),(2,3),(2,5),(3,2)

(3,4),(4,1),(4,3),(5,2)

(5,6),(6,1),(6,5) }

n(B) = { 15 }

P(B) = n(B)÷n(S)

P(B) = 15÷36

P(B) = 5÷12 or 5 upon 12.

if you are satisfy with my ans then mark me as a brainlist

if there is something wrong then kindly rectify it