Question

Two dices are thrown find the probability of getting a multiple of 3of 4 as the sum

Answer 1

Total possible outcomes=

{ (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6)

(2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6)

(3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6)

(4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6)

(5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6)

(6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6)}

Favourable outcomes=

(1,2) (1,3) (1,5) (2,1) (2,2) (2,4) (2,6) (3,1)

(3,3) (3,5) (3,6) (4,2) (4,4) (4,5) (5,1) (5,3)

(5,4) (6,2) (6,3) (6,6)

Probability= 20/36

= 5/9