Two dices are thrown simultaneously. The pribability of getting the sum of numbers appearing on the two dice which is divisible by both 3 and 2 is:
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it is 6 divided by 12
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(sample space) s={ (1,1)............ (6,6)} so n(s)=36
suppose giving event is A
so, A={(1,5), (2,4), (3,3), (4,2), (5,1), (6,6)}
so n (A)=6
n (p)=n (A)/n (S)
so probability =1/6
I hope it will help you
suppose giving event is A
so, A={(1,5), (2,4), (3,3), (4,2), (5,1), (6,6)}
so n (A)=6
n (p)=n (A)/n (S)
so probability =1/6
I hope it will help you
Rohan409:
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