Question

two dices are thrown simultaneously the probability that both the dice will show odd number is​

Answer 1

Answer:

When two dice are thrown simultaneously

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

So there are 36 equally likely outcomes.

Possible number of outcomes =36.

Let E be an event of getting an odd number on both dice.

Favourable outcomes =(1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)

Number of favourable outcomes =9

P(E)=  

Number of possible outcomes

Number of favourable outcomes

​

 

P(E)=9/36=1/4

Probability of getting an odd number on both dice is 1/4.

Answer 2

Answer:

probability of getting odd number on both dice = 1/4

Step-by-step explanation:

total no of outcomes when 2 dices are thrown = 36

favourable no of outcomes ( such that both the dices show odd number) = 9

( the fav outcomes are (1,1) , (1,3) , (1,5) , (3,1) , (3,3) , (3,5) , (5,1) , (5,3) , (5,5) )

therefore,

Probability = 9/36

= 1/4

i hope u understand and this helps!! :)