Question

Two dices are tossed at the same time. What is the probability that at least one of the two numbers would be prime? (Assume 1 as not a prime number)

1/2

5/6

3/5

3/4​

Answer 1

Answer:

Two dice are rolled simultaneously, then

Total outcomes =6×6

=36

Prime number of both the side =(2,2),(2,3),(2,5),(3,2),(3,3),(3,5),(5,2),(5,3),(5,5)=9

Therefore,

Probability P(E)= ( Favourable outcomes )/ ( Total outcomes)

=9/36

=1/4

Answer 2

Answer:

1/2

Step-by-step explanation:

no. of possible outcomes=1,2,1,2 then outcomes =4

Now prime no=2,2 then prime no. occurs =2

let A be the event that prime no. occurs

then P(A) =2/4 =1/2