Question

two die are thrown simultaneously , and the probability of 3 will come up atleast once
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Answer 1

Answer: 11/36

EXPLANATION:-

Total no.of outcomes=(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)(2,1) (2,2) (2,3) (2,4) (2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

=36

total no. of favorable outcomes = (1,3)(2,3)(3,3)(4,3)(5,3)(6,3)(3,1)(3,2)(3,4)(3,5)(3,6)

=11

= total no. of outcomes / total no. of favorable outcomes

=11/36 ans.